思路：先对 nums2 用单调栈求每个元素的下一个更大值，存入 Map 缓存；再遍历 nums1 直接查 Map 得结果。时间复杂度 O(len1 + len2)。
"The BOA will update surgeons with developments so they can treat their patients as the situation develops," he added.
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Раскрыты подробности о договорных матчах в российском футболе18:01